\(\left( {u \pm v} \right)' = u' \pm v'\)

\(\left( {u.v} \right)' = u'v + uv'\)

\(\left( {\dfrac{u}{v}} \right)' = \dfrac{{u'v - uv'}}{{{v^2}}}\)

Hệ quả: \(\left( {\dfrac{1}{u}} \right)' =  - \dfrac{{u'}}{u^2}\)